$\sin^4x=\sin^2x-\sin^2x\cos^2x$
$10x^2+2\left(2x+2\right)$
$\left(\frac{m^9-1}{m-1}\right)$
$5x+1-x+16-17x$
$\lim_{x\to\infty}\left(\frac{e^x-x-1}{cos\left(2x\right)-1}\right)$
$\frac{\left(15-18+21\right)}{-9}$
$\frac{dy}{dx}=\frac{1+x}{x\cdot y^{13}}$
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