$\frac{x^3-8}{x^4}$
$4x^3-8x^2-9x+18$
$10+\left(11-\left(12+\left(13-14\right)\right)\right)$
$2a^2\left(2a+3b-2c\right)$
$\left(1-\sin\left(x\right)^2a\right)\left(1+\tan\left(x\right)^2a\right)=1$
$y'=y-t$
$x\:-\:by\:=\:-1$
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