$\int-3x\cdot e^{10x}dx$
$\frac{dy}{dx}=\frac{y+yx^2}{x^2}$
$\frac{d}{dx}yx^2=8$
$-3\left(x+2\right)$
$\frac{ds}{dt}=ln\left(t\right)+4\left(t\right)$
$\frac{dy}{dx}=\frac{2y^3+y}{x\left(1-y^2\right)}$
$\sqrt[2]{\infty-4}$
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