$3x-6x^2+9^3$
$4\left(6-2y\right)$
$\lim_{x\to0}\:\frac{6cosx+6}{\left(x-\pi\right)^2}$
$\frac{cos\:2x}{2\:sin\:2x\:+cos\:2x}=\frac{1}{2tan2t\:+1}$
$-11-\left|\left(+6\right)-\left(+4\right)\right|$
$x^2+18x+4=0$
$\left(-1.5\right)+3+3\left(-1\right)$
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