$9x+4>10$
$\left(x+\sqrt{10}\right)^2$
$\frac{x^3}{4-x}$
$6-3\cdot2+4\cdot1-5+13-8$
$x^2+10x=-50$
$\lim_{x\to\infty}\frac{3e^x+7}{9lnx+7}$
$-3n+7+6n-2$
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