$-2x\ge-8$
$-16-3-6+3+6+2-6+2-5-1$
$-34-\left(-27\right)$
$\frac{tag\:x-sen\:x}{sen^3x}=\frac{1}{cos\:x\:+cos^2x}$
$14\cdot21\cdot\left(-1\right)$
$1,194+1,248$
$\frac{\left(x^4\:-\:6x^3\:-25x^2-5x\:+\:9\right)}{\left(x+3\right)}$
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