$\frac{dx}{dy}=\sin\left(2y\right)-2x$
$x+5=-14$
$\frac{dy}{dx}=\frac{\sqrt{1-y^2}}{2\sqrt{x}}$
$y=\cos\left(3x^2+2x\right)$
$\left(v+9\right)\left(v+4\right)=0$
$\lim_{x\to\frac{\pi}{2}}\left(\frac{\tan\left(x\right)}{\tan\left(4x\right)}\right)$
$a^3+2a-a^2+4$
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