$\frac{dy}{dt}-t^4y^2=0$
$\lim_{x\to0}\left(\frac{24}{x}-\frac{24}{e^x-1}\right)$
$4-7\cdot9$
$x^2+8x+14=0$
$6\left(4y+3x\right)-12$
$\sin\left(x\right)-\:\left(\sin\left(x\right)\cos^2\left(x\right)\right)=\sin^3\left(x\right)$
$4+1-9-10+6$
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