$\int\frac{1}{6z}dz$
$\sin\:^4\left(\frac{x}{2}\right)-\cos\:^4\left(\frac{x}{2}\right)=\frac{1}{2}$
$\lim_{x\to-\infty}\frac{1-5x^2}{3+4x+x^5}$
$\frac{3}{2\:}x+1>2x-\frac{4}{3}$
$x^2-15x$
$\frac{1}{x^2-6x+8}$
$9+x=52$
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