$6.5\cdot6.5$
$\left(\frac{1}{cosx}-tanx\right)^2=\:\frac{1-sinx}{1+sinx}$
$\left(4x+3y-z\right)\left(4x+3y+z\right)$
$3x^2-3x+6-x+3$
$5x+2\le3x+6$
$4-25x^2=0$
$\cos^2a\tan^2a=1-\cos^2a$
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