limx→∞(1+9x)x\lim_{x\to\infty}\left(1+\frac{9}{x}\right)^xx→∞lim(1+x9)x
6x2−1x2y+5x2y6x^2-1x^2y+5x^2y6x2−1x2y+5x2y
∫1∞(1x.8)dx\int_1^{\infty}\left(\frac{1}{x^{.8}}\right)dx∫1∞(x.81)dx
x2−1=−5xx^2-1=-5xx2−1=−5x
(x+2)2+2(x−2)−6\left(x+2\right)^2+2\left(x-2\right)-6(x+2)2+2(x−2)−6
(16x2y−2)−12\left(\frac{16x^2}{y^{-2}}\right)^{-\frac{1}{2}}(y−216x2)−21
x3+2x2+x−4x^3+2x^2+x-4x3+2x2+x−4
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