$\frac{3^{-2}}{3^{-3}}$

$12a^2b^3c-24ab^2c^2+48ab^3c^3-36abc^2$

$-14-2\left(-4+12\right)$

$18+3.\left(8-12\right)-4.^{\left[5-3.\left(6+3-5.2\right)\right]}$

$\frac{\sin\left(x\right)\left(\sin\left(x\right)+1\right)}{1+\sin\left(x\right)}=\sin\left(x\right)$

$7>\frac{x}{4}$

$x^4+16x^2$