$\left(2a-4g^3\right)^3$
$12x-3\le9x$
$\frac{m}{\left(3+x\right)\left(6-x\right)^2}$
$\left(\frac{2}{7}m+4\right)\left(\frac{2}{7}m-4\right)$
$\left(5\right)-\left(+7\right)\cdot\left(-2\right)+\left(+5\right)-\left(-3\right)$
$\left(2m^2-7\right)\left(2m^2-\:7\right)$
$\left(\frac{4}{3}d+a\right)^3$
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