$\left(a+6\right)^3$
$\left(\:6a+b\right)^2$
$5\le\frac{3x+1}{2}$
$\frac{x-2}{x-2}$
$\left(3x-5y-10z\right)\left(3x-5y-10z\right)$
$15x\frac{3}{5}$
$29^0$
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