$6a^{8}b^{8}\quad3a^{5}b^{2}$
$\cot^4\left(x\right)+\cot^2\left(x\right)=\cot^2\left(x\right)\cdot\csc^2\left(x\right)$
$7-32-45-6+12-45$
$6.8\cdot3.25\cdot1.6$
$\left(\frac{3^{3x\:-\:3}\:}{27^{x-1}}\right)$
$tg\alpha\:\cdot cos\alpha\:\cdot cosec\alpha\:=1$
$x\left(8+9x\right)$
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