$+3-10+5-15\left(3\right)$
$7x-1>5$
$60\cdot60$
$400a^{10}+40a^5+1$
$\frac{\left(x^6\right)}{x-1}$
$\int\frac{\left(3x+2\right)}{\left(x^2-4\right)}dx$
$9x^2-24x-16$
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