$s^4+5s^2+4$
$\frac{x^2+3x+2}{x+3}$
$\int\:\:2x^2\left(6x^3+3x^{-2}\right)dx$
$4x^2-12x=0$
$11x>7x-28$
$\frac{\left(4x^2\:yz^{-1}\right)^{-10}}{\left(1024x^6\:y^5\:z^{-4}\right)^{-2}}$
$-4\left(-3h+3\right)-h$
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