$\left(2x+1\right)\left(2x\:-\:1\right)\left(4x^4-\:5\right)$
$a-b\:=c+d$
$\frac{2}{3}x+4>6$
$\frac{2x^4+3x^3+4x^2+5x+6}{2x-1}$
$-\left(-4\right)$
$5x^2-23x+12$
$\int\left(e^x\sqrt{16-e^{2x}}\right)dx$
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