$\lim_{x\to\infty}\left(\frac{\sqrt{9x+1}}{x+4}\right)$

$\frac{8x^2+2x^3+3}{x^2+2x-1}$

$3x^{2}+2x-5$

$\left(+5\right)-\left(+2\right)-\left(4+6-1\right)-\left(-8-2+5\right)$

$0,6^{\infty}$

$-5\cdot\left[\left(-2\right)^2\cdot\left(-2\right)^3\:\right]+\left[\left(-2\right)^3\cdot\left(3-5\right)^2\:\right]^0\:$

$\left(\frac{7}{6}x^3-\frac{3}{2}\right)\left(\frac{7}{6}x^3-\frac{3}{2}\right)$