limx→π(x2−π23+sinx)\lim_{x\to\pi}\left(\frac{x^2-\pi^2}{3+sinx}\right)x→πlim(3+sinxx2−π2)
34ab+18ab+2ab34ab+18ab+2ab34ab+18ab+2ab
(−2m7p53a2b2)3\left(\frac{-2m^7p^5}{3a^2b^2}\right)^3(3a2b2−2m7p5)3
x2−9x−27=0x^2-9x-27=0x2−9x−27=0
(−5)(−2)(8)(4)\left(-5\right)\left(-2\right)\left(8\right)\left(4\right)(−5)(−2)(8)(4)
∫3x2+5x+1(x−1)(x+2)2dx\int\frac{3x^2+5x+1}{\left(x-1\right)\left(x+2\right)^2}dx∫(x−1)(x+2)23x2+5x+1dx
5+2\sqrt{5+2}5+2
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