$\frac{3y^{-1}}{4yx^3}$
$6\sin^2\left(60\right)+5\cos\left(60\right)$
$\left(3-6\right)+\left(4-3\right)-\left(8-5\right)-3$
$\lim_{x\to0}\left(\frac{x}{\ln\left(x+1\right)}\right)$
$4\left(3+k\right)$
$\left(4x^2\right)^3\left(3x^6\right)^4$
$-s-4s-7s$
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