$\frac{1}{\sec\left(x\right)}+\frac{\sin^2\left(x\right)}{\cos\left(x\right)}=\sec\left(x\right)$

$\left(8b^2+5c^3\right)^2$

$4x^4+4x^3-3x^2-4x-1$

$\int3x^2\cdot\cos\left(x\right)\cdot dx$

$5\left(COS\theta\:+1\right)=5$

$6\:+\:-1\left(14\:-\:8\right)$

$\int_1^2\frac{4x^2-7x-12}{x^3-x^2-6x}dx$