$\frac{\left(1+\frac{1}{x}\right)}{\left(8-\frac{1}{x}\right)}$

$\int\frac{x}{\left(2-4x^2\right)^3}dx$

$2-\left|-7\left(7-2\right)+1\right|-4$

$\left(2g-4\right)\left(2g+4\right)$

$\frac{\ln\left(1+x\right)}{x\left(1-\cos\left(x\right)\right)}$

$\left(-6\right)\cdot\left(+2\right)+\left(+3\right)-\left(6+3-2\right)$

$\csc\left(x\right)=4.9$