$3x+4y+x+x$
$\frac{b}{-6}=7$
$f\left(t\right)=90-22\ln\left(t+1\right)$
$\lim_{x\to\infty}\left(\frac{\left(x^4-256\right)}{\left(x-4\right)}\right)$
$\frac{d}{dx}3y^2$
$3x^2-5x+6\cdot4x-2$
$\int\left(4-2m^2\right)^7mdm$
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