$\int\:\left(\frac{3^{x^2-4x}}{\left(2x-4\right)^{-1}}\right)dx$
$3x+2y-5+3y-2x$
$\left(\frac{256}{x^{12}}\right)^{-\frac{3}{4}}$
$8a^2-90=16a$
$5x-8<107$
$5z\le2+4z$
$-3x+8y+4x-19-10y+z$
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