$\frac{y^2}{4}-\frac{x^2}{25}=1$
$4x^{-\frac{3}{8}}$
$\int x\mathrm{sech}^23xdx$
$7ab^2c-19ca^2b$
$\int\frac{2x^2+3}{\left(x^2+2\right)\left(x-3\right)}dx$
$\left|x\right|^2-\left(4\right)^2$
$-\int\frac{x}{x^2+9}dx$
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