$\frac{x^3+1}{x\left(x-1\right)^3}\:$
$\left(9x+1\right)^3$
$\frac{2}{7}a^3b^2c+\frac{4}{21}a^2b-\frac{16}{49}a^3b^3c^3z$
$h\left(x\right)=\left(\ln\left(x\right)\right)\left(3x^3\right)$
$\lim_{x\to\infty}\left(2x^5-4x^3+3x^2-1\right)$
$x^2+9x+6$
$\left(\frac{1}{2}-2x\right)^2$
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