$-4\left(-2\right)\left(-1\right)\left(3\right)$

$\frac{dx}{dt}+\frac{3}{500}x=0,\:6$

$\frac{9x-8}{x\left(x^2+3\right)^2}$

$\left(-3.4+3.2\right)$

$\lim_{x\to\infty}\left(\frac{9x^2}{e^{8x}}\right)$

$\frac{\left(-2\right)^n}{\left(n+1\right)}\cdot\left(x-3\right)^n$

$\frac{x^2-4}{x^3-10}$