$5.\sqrt[4]{3x+1}+3=13$

$\left(\frac{4x^5y^{-5}}{5y^{-6}}\right)^2$

$\left|1\:\:2\right|$

$\left(\frac{3x+2}{x-1}\right)-1>=\left(\frac{2x-1}{x+1}\right)$

$\frac{\cot\:\left(x\right)-\tan\:\left(x\right)}{\csc\:\left(2x\right)}$

$x^2+x^7$

$\frac{1}{a+2}=\frac{2}{a+3}-\frac{3}{a^2+5a+6}$