$6a+9ab+12abc$
$\left(xa+yx2\right)$
$\left(4-3\right)^2-5.\left(2^2-7\right)$
$x^2-3x=7$
$x^2-19x=66$
$\left(x+1\right)^2-\left(x+1\right)$
$\frac{0.3}{0.4}$
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