$\frac{d}{dx}\left(4\:\ln\left(16\right)\right)$
$2a+3=a+5$
$x^2-10x+24=3$
$\frac{7^6}{7^{-2}}$
$\frac{\sin^2\left(2x\right)}{1-\cos^2\left(x\right)}$
$\frac{d}{dx}\left(arcsin\:-\frac{x}{3}\right)$
$7x-3<2x-1$
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