$\frac{\left(3x^4+0x^3-2x^2+3x-1\right)}{x+3}$
$x^2-3x-18$
$\lim_{x\to3}\left(\frac{x^3-4x^2-11x-30}{x-3}\right)$
$59-\left(-19\right)$
$x^2+\:2xy$
$25x^3+30x^2-x$
$\frac{d}{dx}\left(\frac{\left(x+1\right)\left(5x+1\right)\left(9x+1\right)}{\sqrt{4x+1}}\right)$
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