$y'=0.001$
$\left(-5\right)-\left(-36\right)$
$f\left(x\right)=-6x^2-4x$
$4x-11=1$
$\left(y+4\right)\cdot\left(y^2-4y^2+16\right)$
$5-x>2$
$\:\left(a-2\right)^3=\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:$
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