6+32⋅(−9+3)6+32\cdot\left(-9+3\right)6+32⋅(−9+3)
−2sinb−6=sinb−7-2\sin b-6=\sin b-7−2sinb−6=sinb−7
limx→1(2x−2ln(x))\lim_{x\to1}\left(\frac{2x-2}{ln\left(x\right)}\right)x→1lim(ln(x)2x−2)
3c+2x+2b+3a−2b3c+2x+2b+3a-2b3c+2x+2b+3a−2b
−cot(x)−1=0-cot\left(x\right)-1=0−cot(x)−1=0
5x+2\frac{5}{x}+2x5+2
(x +1) + (x +2) + (x +3)\left(x\:+1\right)\:+\:\left(x\:+2\right)\:+\:\left(x\:+3\right)(x+1)+(x+2)+(x+3)
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!