$x^2\le4x+12$
$\frac{2}{3}\sqrt{7x}$
$\lim_{x\to-\infty}\left(\frac{x^3+x^2-3x+2}{x^2-3x+2}\right)$
$\sqrt{2}\sin\:\left(3\theta\:\right)-1=0$
$16-\left|-1\right|$
$\left(-3\cdot7\right)+\frac{10}{5}$
$\mathrm{sech}^2\left(x\right)=1$
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