$\lim_{x\to-1}\left(x+1\right)^2\cdot ln\left(x+1\right)$
$y-4=6$
$21z^2-16z-16$
$-6x+3y-2x+4y$
$15x^4-17^2-4$
$\tan\left(x\right)=\frac{24}{7}$
$\left(\sqrt{5}x+4y\right)\left(\sqrt{5}x-4y\right)$
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