$\sqrt[5]{x^4}+3-12$
$x^{a+1}+y^{x-2}\:^2$
$\lim_{x\to1}\left(2x^2+2x+4\right)$
$\sqrt{\left(\frac{13x}{6}\right)+\left(\frac{217}{144}\right)}+3=x+\frac{41}{12}$
$-0.6^2$
$2x-3x^2+5x^2+4$
$6\sqrt{98a^2b}-9\sqrt{72a^2b}+\sqrt{200a^5}$
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