$\:w^2r^2\:-\:16$
$\int4x^6dx$
$-9\left(3\right)+6\left(-11\right)+8\left(-3\right)$
$\left(-3bc\right)\left(-3bc\right)$
$\sqrt{80ab^2}$
$\left(-7\:+\:4\right)\:+-\:14\left(-1\right)\:$
$\lim_{x\to\frac{4}{3}}\left(\frac{2-3x}{x-\frac{4}{3}}\right)$
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