(10x)2−29x−212x+3\frac{\left(10x\right)^2-29x-21}{2x+3}2x+3(10x)2−29x−21
∫π5π2(1−cos2t)dx\int_{\pi}^{\frac{5\pi}{2}}\left(\sqrt{1-cos^2t}\right)dx∫π25π(1−cos2t)dx
−(y3+5y+4)-\left(y^3+5y+4\right)−(y3+5y+4)
2x2−32x+20=02x^2-32x+20=02x2−32x+20=0
2x3−5x+6x−3x+2\frac{2x^3-5x+6x-3}{x+2}x+22x3−5x+6x−3
∫x−8x2+8dx\int\frac{x-8}{x^2+8}dx∫x2+8x−8dx
u + (v + w) = (u +v) + wu\:+\:\left(v\:+\:w\right)\:=\:\left(u\:+v\right)\:+\:wu+(v+w)=(u+v)+w
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