$\lim_{x\to0}\left(6x^3+3x^2-5\right)$

$\frac{dy}{dx}=\frac{x^9}{y}$

$2x\left(x+2\right)^2-8\left(x^2+x\right)=3x^3$

$\sin\left(x\right)=-0.6428$

$\left|\left(-5\right)^2\right|^6$

$\lim_{x\to0}\left(\frac{\sqrt{x-\sin\left(x\right)}}{x^{\frac{3}{2}}}\right)$

$2x^3+4x^2=0$