$3+x=16$
$\frac{sen^4x-cos^4x+1}{1+cotan^2x}$
$x+12=1$
$\frac{2-p}{p}=p$
$\frac{d}{dx}\left(y=-5x^2+x\right)$
$\left(7x+5\right)\left(4x-3\right)$
$\frac{dx}{dt}=x-t$
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