$3x^{-2}y^{-\frac{1}{3}}=3x$
$2x\left(x-1\right)$
$x^2y^3-12xy^2$
$\left(-5\right)x\left(+15\right)$
$3a\:\:\:\:-\:\:2b\:\:\:\:-\:\:5a\:\:\:\:+\:\:4b\:\:\:\:-\:\:6a\:\:\:\:+\:\:3b$
$\frac{6x}{x+3}=\frac{5x}{x+5}-\frac{36}{x^2\:+8x+15}$
$8\cdot\left(x\:+\:\frac{1}{2}\right)\:<\:2\cdot\left(\:x\:+\:\frac{1}{2}\:\right)$
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