$c^8-9$
$tan\left(x+\frac{\pi\:\:}{\:4}\right)=\frac{tan\:x\:+1}{1-tan\:x}$
$\lim_{x\to0}\left(\frac{\ln\left(\sin\left(x\right)\right)}{\ln x\left(x\right)}\right)$
$\sqrt[5]{2x^2y}\cdot\:\sqrt[5]{16x^3y^4}$
$\left(n^2+\:2n\right)^{\left(\frac{1}{2}\right)}\:-\left(n^2+n\right)^{\left(\frac{1}{2}\right)}$
$6x^2-4x+34=0$
$2^3-2^2-2+2$
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