$x+1>2x+4$

$\frac{1}{\cos\left(x\right)}-\tan\left(x\right)\frac{1}{\sin\left(x\right)}+1=\frac{1}{\tan\left(x\right)}$

$\frac{d^2}{dx^2}\left(sin\left(\frac{1}{2}x\right)\right)$

$6\left(x^2-1\right)-2\left(x+1\right)$

$\left(5^2\right)^{-2}$

$\left(+1\right)+\left(+1\right)+\left(+1\right)+\left(-2\right)+\left(+1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(+2\right)+\left(+1\right)+\left(-1\right)+\left(+1\right)$

$\frac{d}{dx}\left(ln\left(x\right)\right)^{5sec\left(x\right)}$