$\int\frac{-10x-2}{\left(x+1\right)^2}dx$
$\lim_{x\to1.9}\left(\frac{x-2}{x^2-4}\right)$
$4 y ^ { 2 } - 16$
$\left(x+1\right)dy=\left(x+6\right)dx$
$7x^6\left(5\right)$
$15x\:-\:12\:\le\:9x\:-\:15.$
$\frac{x^5}{x^2-1}$
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