5(3x−1)−20<2(3x+1)5\left(3x-1\right)-20<2\left(3x+1\right)5(3x−1)−20<2(3x+1)
x2+16x−3=0x^2+16x-3=0x2+16x−3=0
6x3+19x2+8x− 5\:6x^3+19x^2+8x-\:56x3+19x2+8x−5
4x2−4x+74x^2-4x+74x2−4x+7
13⋅621^3\cdot6^213⋅62
limx→∞(8+5n)\lim_{x\to\infty}\left(8+\frac{5}{n}\right)x→∞lim(8+n5)
(7c2−4c)2\left(7c^2-4c\right)^2(7c2−4c)2
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