$\frac{2}{x+4}+\frac{8}{x}=\frac{32}{x^2+4x}$
$y^2-2y-168\le0$
$15x^2-68x-64$
$\int\frac{3x+4}{x^2+7x-18}dx$
$\frac{m\:}{9}+\frac{2}{3}=\frac{7}{3}\:$
$\frac{dy}{dt}=y^2-6y-16$
$200\cdot\left(-3\right)$
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