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$-2\:+\:44\:+\:1$
$\frac{128}{-8}$
$x^3-3x^2+4$
$\int\left(5^{2x+3}\right)dx$
$\frac{6x-3}{x+2}\le5$
$x^2+2x=c$
$3x-2\left(4x-7\right)\ge9$
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