$\int ( 4 x - 3 ) ^ { 6 } d x$
$\lim_{x\to0}\left(\frac{sin\left(2x^2\right)}{cos\left(x\right)-1}\right)$
$4y^2\:=0$
$5+5x^3$
$\left(n^2+\frac{7}{2}\right)\left(n^2-5\right)$
$\int\left(x^2+1\right)^95x\:dx$
$\lim_{n\to2}\left(\cos\left(\frac{n}{\pi}\right)\right)$
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