$\left(4\right)-\left(-4\right)\ge8$
$\frac{\cos\left(2x\right)}{\sin^2\left(x\right)}=\cot^2\left(x\right)-1$
$2-\left(-2\left(x+1\right)\right)$
$-7+4-1$
$10+8b=6b-8$
$4x^2-13x+10=0$
$5x\cdot4x+5x\cdot3-6\cdot4x-6\cdot3$
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